Constructor and Description |
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RandomAxe() |
Modifier and Type | Method and Description |
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void |
forArborist(Arborist arborist)
Who's using this axe?
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boolean |
isSpecialist()
Is this a specialist axe?
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java.util.List<Family> |
select(ParseTree tree,
ForestNode forestNode,
int count,
java.util.List<Family> choices)
Select a branch from a list of branches.
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boolean |
wasAmbiguousSelection()
Was the previous selection ambiguous?
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public boolean isSpecialist()
Axe
A specialist axe can consider every tree in the forest differently every time it is used. A non-specialist axe considers every tree at most once and returns all the trees that are selected.
isSpecialist
in interface Axe
public java.util.List<Family> select(ParseTree tree, ForestNode forestNode, int count, java.util.List<Family> choices)
Axe
In an ambiguous forest, some nodes will have more than one possible choice. In any given tree, only one choice may be selected. This function is called to make the selection.
There will always be at least one element in the choices list when the method is called. The method must return at least one.
The first node in the list returned is the choice selected for the tree currently under construction. If only one choice is returned, the node becomes unambiguous on subsequent parses, the same selection will always be used. If additional choices are returned, they will be considered on subsequent parses. Note that if you want the selected choice to be considered on future parses, it must appear in the list twice. It is the only node that may appear twice.
public boolean wasAmbiguousSelection()
Axe
This method asks if the previous selection was ambiguous. If the axe ever indicates that
an ambiguous selection was made, the resulting parse is considered ambiguous. For example, the
SequentialAxe
always returns true because it treats all choices as equivalent.
The PriorityAxe
only considers a selection ambiguous if there wasn't a uniquely highest
priority selection.
wasAmbiguousSelection
in interface Axe